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Arithmetic Progression

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1,3,5,7...is an example of arithmetic progression, where common difference between any two successive terms is 2.

Arithmetic Progression

Things to know 💡 :-

nth term

nth term = first term + (n -1) x common difference
tn = a + (n-1)d

Sum of first n term

Sn = (n/2)[2a + (n-1)d]
a :- first term
d :- common difference

Playground 🎉

See solved examples and practice as much as you want.

First term of an A.P. is
It's common difference is
And value of n is
nth term is
Sum of first nth term is


Relationship between n and Tn can also be visualized as shown below :-
(click on the box to see the graph) Edit this page.

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